IV fluids: How to easily calculate what your really giving.
I give this mini lecture quite often to the residents and medical students during the course of the rotations. I thought I would pass this on to you all as well.
Question for you. How many grams of Salt are you giving your patient when you give a liter bag of 'normal saline?'
So let's start with the basic concept of 0.9% Saline.
What does the 0.9% actually mean?
Well 0.9% is a standard measure, in this case indicating 900 mg/dL.
So that's 900 mg of sodium chloride per 100 cc or 9000 mg (9 grams) per 1 liter bag of normal saline!
My canned joke here is your giving NS at 100 cc/hr=2.4 Liters/day x 9 grams/liter is over 20 grams of salt but....you have him on a 2 gram sodium diet. Good thinking :) 🤦♂️
Ok so how many grams of sodium are in half normal saline?
Well of course you would say 4.5 grams and you would be correct but let's look at the math.
0.45%=450 mg/dL x10 dL=4500 mg of salt/L of 1/2 or 0.45% saline.
Now the deeper question. So how many MEQ per liter of normal saline, or 1/2 Normal saline. 🤔
It's easier than you think to calculate that.
Sodium chloride has a molar mass of 58.44 g/mol (google search <1 second)
If you have a bag of 0.45% normal saline and, as above, you have 4.5 grams/Liter of Normal saline then to figure out the meq/L...
Take 4.5 g/L and divide by 58.44 g/mol-->0.077 mol/L convert to milimoles by x 1000 and you get 77 meq/L of Sodium and 77 meq/l
of Chloride so grand total=154 meq/L.
Let's take this one step deeper. Say you have your 1 liter bag of D5W. You’ve made your patient NPO after midnight.
Question. How many CALORIES are in this bag?
D5W is D5%
5% is 5 grams/dL and so 50 grams/L of dextrose.
A Carbohydrate is 4 kcal/gram so 200 calories in one bag of D5W.
It turns out due to the nature of Dextrose, a gram of Dextrose is actually 3.4 Kcal so it is 3.4 x50 which is 170 calories but you get the idea.
Last one. Let's say you want to make a bag of 0.2% saline with 40 meq KCL.
How many grams of Sodium chloride?
Correct 0.2= 200 mg/dL x10=2 grams
We know already there is also 40 meq KCL
So how many meq of solute is this bag total ?
2 grams of NaCl/L divided by 58.44 g/mol is 0.034 mol/L of Na and 0.034 mol/L of Chloride
Multiply by 1000 for meq and you get...68 meq NaCl + 40 meq KCL=108 meq/L quite a hypotonic solution.
Hope that helps explain what’s in fluids and how to easily figure out what your giving or getting!
Please check out our website for a look at UreaAide, a better tasting lower cost Urea for SIADH.
Comments
Post a Comment